b^2+4b-117=0

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Solution for b^2+4b-117=0 equation:


Simplifying
b2 + 4b + -117 = 0

Reorder the terms:
-117 + 4b + b2 = 0

Solving
-117 + 4b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-13 + -1b)(9 + -1b) = 0

Subproblem 1

Set the factor '(-13 + -1b)' equal to zero and attempt to solve: Simplifying -13 + -1b = 0 Solving -13 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '13' to each side of the equation. -13 + 13 + -1b = 0 + 13 Combine like terms: -13 + 13 = 0 0 + -1b = 0 + 13 -1b = 0 + 13 Combine like terms: 0 + 13 = 13 -1b = 13 Divide each side by '-1'. b = -13 Simplifying b = -13

Subproblem 2

Set the factor '(9 + -1b)' equal to zero and attempt to solve: Simplifying 9 + -1b = 0 Solving 9 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-9' to each side of the equation. 9 + -9 + -1b = 0 + -9 Combine like terms: 9 + -9 = 0 0 + -1b = 0 + -9 -1b = 0 + -9 Combine like terms: 0 + -9 = -9 -1b = -9 Divide each side by '-1'. b = 9 Simplifying b = 9

Solution

b = {-13, 9}

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